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“凤凰卫视”“凤凰网”共诉“凤凰通讯社”，获赔500万！

2020-08-06 598阅读同路君

凤凰网与凤凰卫视分别是华语媒体中极具影响力的知名互联网资讯门户网和电视媒体，两者均属凤凰集团旗下已经成为家喻户晓的品牌，在一般消费者中享有极高的知名度。

但有人却打着“凤凰”集团的名号大肆的“招兵买马”，在商标和商号中均使用“凤凰”字样，且使用近似凤凰图形logo！

近日，海淀法院对凤凰卫视和凤凰网起诉假凤凰媒体——“凤凰通讯社”一案作出一审判决，认定“凤凰通讯社”构成商标侵权和不正当竞争，并赔偿500万元。

案件简介

原告凤凰卫视商标有限公司（凤凰卫视）、北京天盈九州网络技术有限公司（凤凰网）是全球知名媒体，依法在第38类于“电视和无线电广播服务；通过电子、电脑等各种通讯方式来传送数据和信息”等项目上对“凤凰卫视”、 “鳳凰衛視”、“”、“鳳凰網”，以及在第41类于“安排组织会议；节目制作；新闻记者服务；在线电子书籍和杂志的出版”等项目上对“凤凰卫视”、“鳳凰網”享有商标专用权。

自上世纪九十年代，“凤凰”作为原告商标及商号的显著部分，经过长期宣传和持续使用，已经为一般大众所熟知，并享有极高的知名度。

被告凤凰佳艺（北京）文化传媒有限公司（凤凰通讯社），未经原告许可通过多种形式（包括但不限于在经营场所、门牌、商品、包装、宣传材料、名片、网站和其他宣传媒体上或活动中等）使用“凤凰”、“”等标示。

并使用含有“凤凰佳艺”、“香港凤凰通讯社有限公司”或“凤凰通讯社有限公司”的企业名称，冒称“凤凰通讯社是继凤凰集团的凤凰卫视和凤凰网诞生之后又一新闻媒体机构”，从事新闻通讯、新闻报道、新闻记者服务、节目制作等相关服务。进行虚假宣传，构成不正当竞争。

故两家公司诉至北京海淀法院，请求法院判令被告立即停止侵权、消除影响、赔偿原告经济损失1000万元。

被告凤凰通讯社则辩称，公司具有独立的名称、经营范围和对外标识，与两原告经营的品牌、商标不具有关联性，两原告认为凤凰通讯社侵犯其商标权并存在不正当竞争的主张没有事实和法律依据。

此外，公司自成立以来尚未实际经营，两原告要求赔偿经济损失、赔礼道歉等诉求没有事实和法律依据。

法院受理

近日，北京海淀法院通报此案的一审判决结果。

法院审理后认为，被控侵权标识“凤凰”与原告注册商标构成近似商标。

从公众的认知角度来看，被告的上述行为，极易导致相关公众混淆误认，且被告在对外宣传中也积极将“凤凰通讯社”与“凤凰卫视”“凤凰网”相联系，该行为构成侵犯商标权。

此外，法院认为，凤凰通讯社及其法定代表人多次在公开场合发布声明称，“凤凰通讯社是继凤凰卫视和凤凰网之后，又一个与之并行的，具有国际影响力和竞争力的新闻媒体机构”，该行为已经构成虚假宣传。

故法院认定，凤凰通讯社的以上行为，意欲利用原告知名度误导相关公众，非法争夺原告市场利益，该行为构成不正当竞争。

此外，考虑到被告侵权时间长、范围广、侵权情节恶劣等因素，应承担经济损失赔偿额。故海淀法院作出一审判决，要求被告公司立即停止侵权，并赔偿两原告经济损失500万元。

被告“凤凰通讯社”无论从商标、商号及虚假宣传方面，均具有“傍名牌”的明显恶意。

即，明知原告凤凰卫视和凤凰网在媒体领域的极高知名度，仍借用各种形式或方式进行恶意模仿，误导相关公众，牟取非法利益。

被告侵权故意明显、侵犯范围之广（覆盖海内外）以及侵权时间持续等，已经给原告造成了严重的商誉及经济损失。

对此恶意侵权行为法院予以严厉打击和处罚，也彰显我国加大知识产权保护力度和维护市场秩序公平公正健康发展的决心。

内容来源：泓翎

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1064:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'and status=0 ) LIMIT 1' at line 1 [ SQL语句 ] : SELECT COUNT(*) AS tp_count FROM `ln_position` WHERE ( parent_id= and status=0 ) LIMIT 1
1054:Unknown column 'UID' in 'where clause' [ SQL语句 ] : SELECT `position_id` FROM `ln_member` WHERE ( id=UID ) LIMIT 1
1064:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'and status=0 ) LIMIT 1' at line 1 [ SQL语句 ] : SELECT COUNT(*) AS tp_count FROM `ln_position` WHERE ( parent_id= and status=0 ) LIMIT 1

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